Hydraulic Cylinder and Power Unit Selection Method

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Step 1 · Determine the basic specificationsTo design and manufacture a hydraulic elevator, the basic specifications must be determined first. Based on these, the cylinder diameter and the power unit's pump and motor are selected.
Basic specificationSymbolUnitDescriptionExample data
Rated loadWkg3,000 kg
Car weightCWkg3,000 kg
Rated speedVm/min20 m/min
TravelTrmm8,200 mm
RopingRP1:1Direct – RP = 1Indirect RP = 2
1:2Indirect – RP = 2
StrokeLIndirect(Travel/RP) + extra length(8,200/2) + 250 = 4,350 mm
Power supplyVoltage (V), frequency (Hz)380 V, 60Hz
ApplicationPassenger, freight, car, etc.Freight

> Cylinder rod set to 195 mm.

Step 2 · CalculateBased on the basic data above, the pressure, flow rate (pump capacity), power (motor selection), actual speed and tank size are calculated as follows.
ItemSymbolTypeFormulaValueUnitSelection result
Cross-sectional areaAFormula(Rod outer diameter ÷ 2)² x 3.14 =298.5cm²Diameter 195 mm
Calculation(19.5 cm ÷ 2)² x 3.14 =
Operating pressureP1Formula{(Rated load + Car weight) x RP} + Other weightArea42.2kg/cm²
Calculation{(3,000 + 3,000) x 2} + 590298.5
Total pressureP0FormulaOperating pressure(P1) + Friction =47.2kg/cm²
Calculation42.2 + 5 =
Flow rateQFormula(Area x Speed) ÷ (RP x 10) =300ℓ/minUse SM 250L
pump
Calculation(298.5 x 20) ÷ (2 x 10) =
PowerMpFormula(Flow rate x Total pressure) ÷ (612 x 0.8) =28.9kwUse 29 kw
motor
Calculation(300 x 47.2) ÷ (612 x 0.8) =
Actual speedVFormula(Actual pump flow x 2 x 10) ÷ Area =20.1m/min
Calculation(300 x 2 x 10) ÷ 298.5 =