Cylinder Safety Factor

Calculation data

Quotation no.1410-0105Quotation date14-10-25
Company nameFor catalogSite nameAAA
Quantity1Contact person홍길동
e-maildn@donam.co.kr
Design specifications
Rated load3,000 kg x 2 = 6,000 kg
Car weight3,000 kg x 2 = 6,000 kg
Rod weight210 kg x 1 = 210 kg
Rope + sheave379 kg x 1 = 379 kg
Total loadWt = 12,589 kg
Travel(8,200 mm ÷ 2) + 250 mm = 4,350 mm
Required speed20 m/min
Roping method2:1 (indirect)
ApplicationPassenger · Freight ◀ · Car · Other 1 · Other 2
Cylinder sizeØ195 mm x 4,350 x 1CyTank (flow) sizeB(335 ℓ) x 1Pu
Cylinder weight337 kg/unitTank weight

Cylinder basic data

ItemOuter diameter (cm)Inner diameter (cm)MaterialTensile strength
(f: kg/cm²)
Tube/rod bottom plate data
SymbolDimensionSymbolDimensionThickness (cm)MaterialTensile strength
TubeTb27.3Tb24.9STKM13380020.0SS-4004100
RodRd19.5Rd17.6STKM13380020.0SS-4004100
Support point factorn1Pump efficiency%90
Yield pointσ2200 kg/cm²Motor efficiency%80

1) Safety factor calculation (S)

ItemFormulaValueCalculation
PipeTube(2.f.thickness:Tt) ÷ {(pressure: P ÷ Cy quantity) x inner diameter(Tb)}7.8(2 x 3800 x 1.2) ÷ {(47.2 ÷ 1) x 24.9}
Rod[{(RD²) - (rd²)}.f] ÷ {2 x (pressure: P ÷ Cy quantity) x (RD²)}7.5[{(19.5²) − (17.6²)} x 3800] ÷ {2 x (47.2 ÷ 1) x (19.5²)}
Bottom plateTube{(4.f) ÷ pressure:P} x {Bt ÷ (tb²)}250.9{(4 x 4100) ÷ 42.2} x (20.0 ÷ 24.9)²
Rod{(4.f) ÷ pressure:P} x {Bt ÷ (rd²)}502.1{(4 x 4100) ÷ 42.2} x (20.0 ÷ 17.6)²

2) Rod buckling strength calculation

ItemSymbolFormulaValueUnitCalculation
Rod wall cross-sectional areaAo{(outer diameter(RD) ÷ 2²) − (inner diameter(rd) ÷ 2²)} x π55.3cm²{(19.5 ÷ 2²) − (17.6 ÷ 2²)} x π
Minimum second moment of areaI[π x {(outer diameter: RD⁴) − (inner diameter: rd⁴)}] ÷ 642,386.3[3.14 x {(19.5⁴) − (17.6⁴)}] ÷ 64
Radius of gyrationY√(second moment of area(I) ÷ rod wall area: Ao)6.6cm√2,386.3 ÷ 55.3
Slenderness ratioλ(maximum free length: L) ÷ (radius of gyration: Y)66.2435 ÷ 6.6

➔ According to the Gordon-Rankine table, slenderness ratio (λ) ≤ 85 x √support point factor(n) → [66.2 ≤ 85 (= 85 x √1)]

Safety factorS{(π²) x E x rod wall area(A)} ÷ {(Wt − rod weight ÷ 2) x (λ²) ÷ Cy quantity}20.9{{(π²) x 2,100,000} x 55.3} ÷ {(12,589 − 379 ÷ 2) x (66.2²) ÷ 1}

Unit selection data

ItemSymbolFormulaValueUnitCalculation
Rod cross-sectional areaA{π x (rod outer diameter(RD) ÷ 2)²} x Cy quantity298.5cm²{π x (9.8²)} x 1
Actual delivery flowQcalculated flow = {A x V} ÷ {roping x 10}300.0ℓ/min← bar
PressurePw{(car weight + load) x roping + other(Wo)} ÷ A42.2kg/cm²{(6000 x 2) + 589} ÷ 298.5
Total pressurePtpressure(Pw) + pressure loss47.2kg/cm²42.2 + 5.0
Required powerMp{(flow(Q) x pressure(Pt)) ÷ 612} ÷ efficiency(%)28.9kw{(300.0 x 47.2) ÷ 612} ÷ 80%
Actual speedV(flow(Q) x roping x 10) ÷ A20.1m/min{(300.0 x 2 x 10) ÷ 298.5}

Unit selection result ➞ 1 unit & 1 cylinder

TypePumpMotorVoltage/frequencyControl valveFGTank typeMinimum required oil volume
1 unit250 L x 129 kw x 1380 V, 60 Hz1.5″ x 1#2B x 1335 ℓ x 1 Cy